| Two stations P and Q are at a distance of 160 km. Two trains start moving from P and Q to Q and P, respectively and meet each other after 4 h. If speed of the train starting from P is more than that of other train by 6 km/h, then find the speeds of both the trains, respectively. |
A) 19 km/h, 13 km/h
B) 13 km/h, 9 km/h
C) 17 km/h, 23 km/h
D) 16 km/h, 10 km/h
E) None of these
Correct Answer: C
Solution :
| Let the speed of both trains be x km/h and |
| \[(x+6)\,\,km/h,\]respectively. |
| Then, according to the question, |
| \[160=x\times 4+(x+6)\times 4\] |
| \[\Rightarrow \] \[160=4x+4x+24\] |
| \[\Rightarrow \] \[40=x+x+6\] |
| \[\Rightarrow \] \[2x+6=40\]\[\Rightarrow \]\[2x=34\] |
| \[\therefore \] \[x=17\] |
| Hence, speeds of both the trains are \[17km/h\] and \[(17+6)\,\,km/h\] i.e. \[17\,\,km/h\] and \[23\,km/h.\] |
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