If \[x=\sqrt{8+\sqrt{8+\sqrt{8...}}}\]and \[y=\sqrt{8-\sqrt{8-\sqrt{8....,}}}\] |
A) \[x+y=1\]
B) \[x+y+1=0\]
C) \[x-y=1\]
D) \[x-y+1=0\]
Correct Answer: C
Solution :
\[x=\sqrt{8+\sqrt{8+\sqrt{8+...}}}\] |
\[{{x}^{2}}=8+\sqrt{8\sqrt{8+\sqrt{8+...}}}\] |
\[\therefore \] \[{{x}^{2}}=8+x\] |
Similarly, \[{{y}^{2}}=8-y\] |
\[\therefore \] \[{{x}^{2}}-{{y}^{2}}=(x+8)-(8-y)\] |
\[(x+y)(x-y)=(x+y)\] |
\[\Rightarrow \] \[x-y=1\] |
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