| A can do a certain work is 12 days. B is 60% more efficient than A. How many days will B and A together take to do same job? [SSC (CGL) 2012] |
A) \[\frac{80}{13}\]
B) \[\frac{70}{13}\]
C) \[\frac{75}{13}\]
D) \[\frac{60}{13}\]
Correct Answer: D
Solution :
| In such questions, we have to calculate the number of days of each worker. |
| In this question, |
| The efficiency of B is 60% more than, A and time taken by A is 12 days. |
| Now, we find the number of days of B's work, |
| By the formula, |
| Time \[=\frac{100}{100+x}\times \]Total days taken by A |
| where, \[x=\] efficiency percentage |
| \[\therefore \]Time taken by \[B=\frac{100}{160}\times 12=\frac{15}{2}\,\,\text{days}\] |
| \[\therefore \](A + B)'s 1 day work \[=\frac{1}{2}+\frac{2}{15}=\frac{5+8}{60}=\frac{13}{60}\] |
| Hence, the work will be completed in \[\frac{60}{13}\]days. |
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