| In the given figure, O is the centre of a circle and \[\angle OAB=50{}^\circ .\]Then, \[\angle BOD\] is equal to |
 |
A) \[130{}^\circ \]
B) \[50{}^\circ \]
C) \[100{}^\circ \]
D) \[80{}^\circ \]
Correct Answer: C
Solution :
| \[OA=OB\]\[\Rightarrow \]\[\angle OBA=\angle OAB=50{}^\circ \] |
| [angle substend by same segments, i.e. radius] |
| In \[\Delta OAB,\]\[\angle OAB+\angle OBA+\angle AOB=180{}^\circ \] |
| \[\Rightarrow \]\[50{}^\circ +50{}^\circ +\angle AOB=180{}^\circ \] |
| \[\Rightarrow \] \[\angle AOB=80{}^\circ \] |
| \[\therefore \]\[\angle BOD=(180{}^\circ =80{}^\circ )=100{}^\circ \] |
You need to login to perform this action.
You will be redirected in
3 sec
