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Banking Quantitative Aptitude Sample Paper Quantitative Aptitude Sample Paper-45

  • question_answer
    Directions: Refer to the pie-chart and the table and answer the given questions,
    Distribution of total number of shirts (linen and cotton) sold by six different stores in 2003.
    Total number = 84000
    Store Respective ratio of number of linen shirts to cotton shirts sold
    A 7 : 5
    B 5 : 6
    C 3 : 2
    D 5 : 3
    E 4 : 3
    F 7 : 3
    What is the difference between average number of linen shirts sold by stores D and E together and average number of cotton shirts sold by the same stores together?

    A) 2920                

    B) 2880  

    C) 2940    

    D) 3140

    Correct Answer: C

    Solution :

    Total number of shirts (linen and cotton) sold by six different store in 2003 = 84000
    Total shirts sold by store D = 12% of 84000
    \[=\frac{12}{100}\times 84000=10080\]
    Number of linen shirts sold by store D
    \[=\frac{5}{8}\times 10080=6300\]
    Number of cotton shirts sold by store D
    \[=10080-6300=3780\]
    Total shirts sold by store E = 28% of 84000
    \[=\frac{28}{100}\times 84000=23520\]
    Number of linen shirts sold by store E
    \[=\frac{4}{7}\times 23520=13440\]
    Number of cotton shirts sold by store E
    \[=23520-13440=10080\]
    Now, average number of linen shirts sold by stores D and E
    \[=\frac{6300+13440}{2}=9870\]
    and average number of cotton shirts sold by stores D and E \[=\frac{3780+10080}{2}=6930\]
    \[\therefore \]Required difference \[=9870-6930=2940\]


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