Banking Quantitative Aptitude Sample Paper Quantitative Aptitude Sample Paper-45

  • question_answer
    What was the day of the week on 17th August, 2010?

    A) Sunday            

    B) Wednesday

    C) Tuesday

    D) Friday

    Correct Answer: C

    Solution :

    Period upto 17th August, 2010
    = (year 2009 + Period from 1.1,2010 to 17. 8.2010)
    Odd days in 1600 yr = 0
    Odd days in 400 yr = 0
    9 yr= (2 leap years + 7 ordinary years)
    \[=(2\times 2+7\times 1)=1\,\,\text{week}+4\,\,\text{days}\]
    = 4 odd days
    Number of days between 1.1. 2010 to 17.8.2010
    = January + February + March + April + May + June + July + August
    \[=(31+28+31+30+31+30+31+17)\,\,\text{days}\]
    = 229 days = 32 weeks + 5 odd days
    Total number of odd days \[=(0+0+4+5)\,\,\text{days}\]
    = 9 days = 1 week + 2 odd days
    Hence, the required day is Tuesday.


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