| Directions: In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate option, [IBPS (PO/MT) 2015] |
| I. \[{{x}^{2}}=9\] |
| II. \[2{{y}^{2}}-19y+44=0\] |
A) If \[x>y\]
B) If \[x<y\]
C) If \[x\ge y\]
D) If \[x\le y\]
E) If relationship between x and y cannot be established
Correct Answer: E
Solution :
| I. \[{{x}^{2}}=9\]\[\Rightarrow \]\[x=\sqrt{9}\]\[\Rightarrow \]\[x=\pm \,\,3\] |
| II. \[2{{y}^{2}}-19y+44=0\] |
| \[\Rightarrow \]\[2{{y}^{2}}-11y-8y+44=0\] |
| \[\Rightarrow \]\[y\,\,(2y-11)-4\,\,(2y-11)=0\]\[\Rightarrow \]\[y=4,\]\[11/2\] |
| \[\therefore \]Relationship cannot be determined. |
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