| Directions: In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate option, [IBPS (PO/MT) 2015] |
| I. \[3{{x}^{2}}+11x+6=0\] |
| II. \[3{{y}^{2}}+10y+8=0\] |
A) If \[x>y\]
B) If \[x<y\]
C) If \[x\ge y\]
D) If \[x\le y\]
E) If relationship between x and y cannot be established
Correct Answer: E
Solution :
| I. \[3{{x}^{2}}+11x+6=0\] |
| \[\Rightarrow \]\[3{{x}^{2}}+9x+2x+6=0\] |
| \[\Rightarrow \]\[3x\,\,(x+3)+2\,\,(x+3)=0\] |
| \[\Rightarrow \]\[(3x+2)(x+3)=0\] |
| \[\Rightarrow \]\[x=-\,\,3,\]\[-\,\,2/3\] |
| II. \[3{{y}^{2}}+10y+8=0\] |
| \[\Rightarrow \]\[3{{y}^{2}}+6y+4y+8=0\] |
| \[\Rightarrow \]\[3y\,\,(y+2)+4\,\,(y+2)=0\]\[\Rightarrow \]\[y=-\,\,2,\]\[-\frac{4}{3}\] |
| \[\therefore \]Relationship cannot be determined. |
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