| By mixing two quantities of sugar in the ratio 2: 3 and selling the mixture at the rate of Rs. 22 per kg, a shopkeeper make a profit of 10%. If the cost of the smaller quantity be Rs. 14 per kg, then the cost of the larger quantity is |
A) 23
B) 24
C) 25
D) 200
Correct Answer: B
Solution :
| \[\text{Gain}\]%\[=\frac{(a+b)z-(ax-by)}{ax+by}\times 100\]% |
| Here, \[a=2,\]\[b=3,\]\[z=22,\]\[x=14\]and \[y=?\] |
| \[10=\frac{(2+3)\times 22-(2\times 14+3\times y)}{2\times 14+3\times y}\times 100%\] |
| \[\Rightarrow \]\[28+3y=\{110-(28+3y)\}\times 10\] |
| \[\Rightarrow \]\[28+3y=820-30y\]\[\Rightarrow \]\[33y=792\] |
| \[\Rightarrow \]\[y=24\,\,\text{per}\,\,kg\] |
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