Banking Quantitative Aptitude Sample Paper Quantitative Aptitude Sample Paper-44

  • question_answer
    Consider the following.
    I. \[{{\sin }^{2}}1{}^\circ +{{\cos }^{2}}1{}^\circ =1\]
    II. \[{{\sec }^{2}}33{}^\circ -{{\cot }^{2}}57{}^\circ =\text{cose}{{\text{c}}^{2}}37{}^\circ -{{\tan }^{2}}53{}^\circ \]
    Which of the above statement is/are correct?

    A) Only I

    B) Only II

    C) Both I and II                 

    D) Neither I nor II

    Correct Answer: A

    Solution :

    We know that, \[{{\sin }^{2}}\theta +{{\cos }^{2}}\theta =1\]is true.
    I. \[{{\sin }^{2}}1{}^\circ +{{\cos }^{2}}1{}^\circ =1\] which is true.
    II. \[{{\sec }^{2}}33{}^\circ -{{\cot }^{2}}57{}^\circ =\text{cose}{{\text{c}}^{2}}37{}^\circ -{{\tan }^{2}}53{}^\circ \]
    Now, \[{{\sec }^{2}}\,\,(90{}^\circ -57{}^\circ )=\text{cose}{{\text{c}}^{2}}57{}^\circ \]
    and \[{{\cot }^{2}}57{}^\circ ={{\cot }^{2}}\,\,(90{}^\circ -33{}^\circ )={{\tan }^{2}}33{}^\circ \]
    \[\therefore \]\[{{\sec }^{2}}33{}^\circ -{{\cot }^{2}}57{}^\circ =\text{cose}{{\text{c}}^{2}}57{}^\circ -{{\tan }^{2}}33{}^\circ \]
    II is not true.


You need to login to perform this action.
You will be redirected in 3 sec spinner