X and Y start walking towards each other at 8: 00 am at the speeds of 3 km/h and 4 km/h, respectively. They were initially 17.5 km apart. At what time do they meet? |
A) 10 : 30 am
B) 10 : 30 pm
C) 11: 30 am
D) 11: 30 pm
Correct Answer: A
Solution :
Let they meet after x h. |
Then, according to the question, |
\[3x+4x=17.5\]\[\Rightarrow \]\[7x=17.5\] |
\[\therefore \] \[x=\frac{17.5}{7}=2.5\,\,h\] |
So, they meet 2.5 h after 8: 00 am. It means they meet at 10: 30 am. |
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