| \[{{(5568\div 87)}^{\frac{1}{3}}}+{{(72\times 2)}^{\frac{1}{2}}}={{(?)}^{\frac{1}{2}}}\] [IDBI (SO) 2012] |
A) \[256\]
B) \[4\]
C) \[\sqrt{2}\]
D) \[16\]
E) None of these
Correct Answer: A
Solution :
| Given, \[{{(5568\div 87)}^{\frac{1}{3}}}+{{(72\times 2)}^{\frac{1}{2}}}={{(?)}^{\frac{1}{2}}}\] |
| \[\Rightarrow \]\[{{(64)}^{\frac{1}{3}}}+{{(144)}^{\frac{1}{2}}}={{(?)}^{\frac{1}{2}}}\]\[\Rightarrow \] \[{{(4)}^{3\,\,\times \,\,\frac{1}{3}}}+{{(12)}^{2\,\,\times \,\,\frac{1}{2}}}={{(?)}^{\frac{1}{2}}}\] |
| \[\Rightarrow \]\[(4)+(12)={{(?)}^{\frac{1}{2}}}\]\[\Rightarrow \]\[(16)={{(?)}^{\frac{1}{2}}}\] |
| \[\Rightarrow \]\[{{(16)}^{2}}={{(?)}^{\frac{1}{2}\,\,\times \,\,2}}=?=256\] |
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