The price of sugar having gone down by 10%, a consumer can buy 5 kg more sugar for Rs. 270. The difference between the original and reduced price per kg is [SSC (CGL) 2013] |
A) 62 paise
B) 60 paise
C) 75 paise
D) 53 paise
Correct Answer: B
Solution :
Let the original price of sugar be Rs. x. |
Then, reduced price of sugar |
\[=x-\frac{10x}{100}=\frac{90x}{100}=\text{Rs}\text{. }\frac{9x}{10}\] |
Now, according to the question, |
\[\frac{270}{9x/10}-\frac{270}{x}=5\] |
\[\Rightarrow \] \[\frac{270/10}{9x}-\frac{270}{x}=5\] |
\[\Rightarrow \] \[\frac{300}{x}-\frac{270}{x}=5\]\[\Rightarrow \]\[\frac{300-270}{x}=5\] |
\[\therefore \] \[x=\frac{30}{5}=6\] |
\[\therefore \]Original price of sugar = Rs. 6 |
Reduced price of sugar \[=\frac{9\times x}{10}=\frac{9\times 6}{10}=\text{Rs}\text{. 5}\text{.40}\] |
\[\therefore \]Required difference \[=(6-5.40)=\text{Rs}\text{. 0}\text{.60}\] or 60 paise |
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