question_answer

The greatest number of six digits exactly divisible by 24, 15 and 36, is

A) 999720 

B) 999629

C) 999320             

D) 999620

Correct Answer: A

Solution :

\[\therefore \]LCM of \[24,\]\[15,\]\[36\]\[=3\times 2\times 2\times 2\times 5\times 3=360\]

Greatest number of 6 digits \[=999999\]

When 999999 is divided by 360, we get 279 as remainder.

\[\therefore \]Required number \[=999999-279=999720\]