| Train X starts from point A for point B at the same time that train Y starts from B to A. Points A and B are 300 km apart. The trains are moving at a constant speed atleast at 25 km/h. The trains meet each other 3 h after they start. If the faster train takes atleast 2 more hours to reach the destination which time will the slower train have definitely reached its destination? (Ignoring the length of trains in crossing) |
A) 4 h after the start
B) 7.5 h after the start
C) 6 h after the start
D) None of the above
Correct Answer: B
Solution :
| Let the speed of X and Y be x km/h and y km/h, respectively. |
| Since, they meet after 3 h, so \[x+y=100\] |
| Since, the faster train takes atleast \[3+2=5\] h to complete the 300 km journey, |
| Hence minimum possible speed for the slower train = 40 km/h at which speed, it will take 7.5 h to complete the journey, i.e.\[\frac{300}{40}=7.5\] |
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