Banking Quantitative Aptitude Sample Paper Quantitative Aptitude Sample Paper-36

A sum of Rs. 6344 is divided into 3 parts and given on loan at 5% simple interest to A. B and C for 2, 3 and 4 yr, respectively. If this amounts of all three are equal to their respective of loan, then B received a loan of

A) Rs. 2112

B) Rs. 2128

C) Rs. 2820

D) Rs. 2802

Correct Answer: A

Solution :

Given, sum = Rs. 6344

We know that the ratio in which the sum was divided in x parts is given by

\[=\frac{1}{100+{{R}_{1}}{{T}_{1}}}:\frac{T}{100+{{R}_{2}}{{T}_{2}}}:\frac{1}{100+{{R}_{3}}{{T}_{3}}}\]

\[=\frac{1}{100+5\times 2}:\frac{1}{100+5\times 3}:\frac{1}{100+5\times 4}\]

[ \[\because \,\,{{R}_{1}}={{R}_{2}}={{R}_{3}}=5\]% ,\[{{T}_{1}}=2\,yr,\,\,{{T}_{2}}=3yr\,\,\text{and}\,{{T}_{3}}=4\,\,yr\] ]

\[=\frac{1}{110}:\frac{1}{115}:\frac{1}{120}\]

\[=\frac{1}{22}:\frac{1}{23}:\frac{1}{24}\]

\[=23\times 24:22\times 24:22\times 23\]

\[=552:528=506\]

Now, B received a loan \[=\frac{528}{1586}\times 6344=\text{Rs}\text{. 2112}\]