| If two pipes function simultaneously the reservoir will be filled in 8 h one pipe fills the reservoir 12 h faster than the other. How many hours does the faster pipe take to fill the reservoir? |
A) 12
B) 16
C) 14
D) 10
Correct Answer: A
Solution :
| Let one pipe take x h to fill the reservoir, so that the second pipe takes \[(x-12)\,\,h.\] |
| \[\therefore \]\[\frac{1}{x}+\frac{1}{x-12}=\frac{1}{8},\]which is satisfied by \[x=24\] |
| \[\therefore \]The faster pipe takes \[(24-12)=12\,\,h\]to fill the reservoir. |
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