| The ratio of the quantities of an acid and water in a mixture is 1: 3. If 5 L of acid is further added to the mixture, the new ratio becomes 1: 2. The quantity (in litres) of new mixture is [SSC (CGL) 2011] |
A) 32
B) 40
C) 42
D) 45
Correct Answer: D
Solution :
| Let the quantity of acid in original mixture be x L and that of water be 3x L. |
| According to the question, |
| \[\frac{x+5}{3x}=\frac{1}{2}\] |
| \[\Rightarrow \] \[2x+10=3x\]\[\Rightarrow \]\[x=10\] |
| \[\therefore \]Quantity of new mixture |
| \[=4x+5=4\times 10+5=45\] |
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