| Directions: In each of these questions, a number series is given. In each series, only one number is wrong. Find out the wrong number. [SBI (PO) 2011] |
| 4, 12, 42, 196, 1005, 6066, 42511 |
A) 12
B) 42
C) 1005
D) 196
E) 6066
Correct Answer: B
Solution :
| \[4\times 2+{{(2)}^{2}}=12\]\[\Rightarrow \]\[12\times 3+{{(3)}^{2}}=45\ne 42\] |
| \[45\times 4\,\,{{(4)}^{2}}=196\]\[\Rightarrow \]\[196\times 5+{{(5)}^{2}}=1005\] |
| \[1005\times 6+{{(6)}^{2}}=6066\] |
| \[6066\times 7+{{(7)}^{2}}=42511\] |
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