| Directions: In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer. |
| I.\[{{x}^{2}}-7x+12=10\] |
| II. \[{{y}^{2}}+y-12=0\] |
A) If \[x>y\]
B) If \[x\ge y\]
C) If \[x<y\]
D) If \[x\le y\]
E) If\[x=y\] or the relationship cannot be Established
Correct Answer: B
Solution :
| I. \[{{x}^{2}}-7x+12=0\] |
| \[\Rightarrow \]\[{{x}^{2}}-4x-3x+12=0\] |
| \[\Rightarrow \] \[(x-4)(x-3)=0\] |
| \[\Rightarrow \] \[x=4,\]\[3\] |
| II. \[{{y}^{2}}+y-12=0\] |
| \[\Rightarrow \]\[{{y}^{2}}+4y-3y-12=0\] |
| \[\Rightarrow \] \[(y+4)(y-3)=0\] |
| \[\Rightarrow \] \[y=-\,\,4,3\] |
| \[\therefore \] \[x\ge y\] |
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