A and B working separately can do a piece of work in 9 and 15 days, respectively. If they work for a day alternately with A beginning, then the work will be completed in |
A) 10 days
B) 11 days
C) 9 days
D) 12 days
Correct Answer: B
Solution :
Work done by A and B in 2 days \[=\frac{1}{9}+\frac{1}{15}=\frac{8}{45}\] |
Work done by both in 10 days \[=\frac{5\times 8}{45}=\frac{8}{9}\] |
Remaining work \[=1-\frac{8}{9}=\frac{1}{9}\] |
Next day, A will do the work. |
\[\therefore \]Work done by A in one day\[=\frac{1}{9}=\]remaining work |
Hence, total days required to complete the work |
= 11 days |
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