| Four quantities are such that their average is same as the average of first three quantities. The fourth quantity is |
A) sum of first three quantities
B) (sum of all four quantities)/4
C) (sum of first three quantities)/3
D) (sum of first three quantities)/2
Correct Answer: C
Solution :
| Let the four quantities be a, b, c and d. |
| According to the question, |
| \[\frac{a+b+c+d}{4}=\frac{a+b+c}{3}\] |
| \[\Rightarrow \]\[3a+3b+3c+3d=4a+4b+4c\] |
| \[\Rightarrow \] \[3d=a+b+c\] |
| \[\Rightarrow \] \[d=\frac{a+b+c}{3}\] |
| = Sum of first three quantities/3 |
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