| The product of two 2-digit numbers is 2028 and their HCF is 13. The sum of numbers is |
A) 65
B) 78
C) 81
D) 169
Correct Answer: C
Solution :
| Let the numbers be 13ac and13y, when x and y are prime to each other. |
| \[\therefore \] \[13x\times 13y=2028\] |
| \[\Rightarrow \] \[xy=\frac{2028}{13\times 13}=12=3\times 4\] |
| \[\therefore \]Numbers\[=13\times 3=39\]and \[13\times 4=52\] |
| \[\Rightarrow \]Sum of numbers \[=39+52=91\] |
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