| There is 81 L pure milk in a container. One-third of milk is replaced by water in the container. Again, one-third of mixture is extracted and equal amount of water is added. What is the ratio of milk to water in the new mixture? |
A) 1 : 2
B) 1 : 1
C) 2 : 1
D) 4 : 5
Correct Answer: D
Solution :
| Given, pure milk in container \[=81\,\,L\] |
| By replacing \[\frac{1}{3}\] part by water, |
| Remaining milk \[81-\frac{1}{3}\times 81=81-27=54\,\,L\] |
| Again, replacing \[\frac{1}{3}\]part by water. |
| \[\therefore \]Remaining milk \[=54-\frac{1}{3}\times 54=54-18=36\,\,L\] |
| Then, quantity of water at last \[=81-36=45\,\,L\] |
| \[\therefore \]Required ratio \[=\frac{36}{45}=\frac{4}{5}\] |
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