| An alloy contains zinc, copper and tin in the ratio 2: 3: 1 and another contains copper, tin and lead in the ratio 5: 4: 3. If equal weights of both alloys are melted together to form a third alloy, then the weight of lead in the new alloy will be [SSC (CGL) 2008] |
A) \[\frac{1}{2}kg\]
B) \[\frac{1}{8}kg\]
C) \[\frac{3}{14}kg\]
D) \[\frac{7}{9}kg\]
Correct Answer: B
Solution :
| Quantity of lead in 1 kg of first alloy = 0 |
| \[\therefore \]Quantity of lead in\[1\,\,kg\] of second alloy\[=\frac{3}{12}=\frac{1}{4}kg\] |
| \[\therefore \]Quantity of lead in \[2\,\,kg\]of new alloy \[=\frac{1}{4}+0=\frac{1}{4}kg\] |
| \[\therefore \]Quantity of lead in \[1\,\,kg\]of new alloy \[=\frac{1}{8}kg\] |
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