| The arrangement of rational numbers \[\frac{-\,\,7}{10},\]\[\frac{5}{-\,\,8},\]\[\frac{2}{-\,\,3}\]in ascending order is |
A) \[\frac{2}{-\,\,3}<\frac{5}{-\,\,8}<\frac{-\,\,7}{10}\]
B) \[\frac{5}{-\,\,8}<\frac{-\,\,7}{10}<\frac{-\,\,2}{3}\]
C) \[\frac{-\,7}{10}<\frac{5}{-\,\,8}<\frac{2}{-\,\,3}\]
D) \[\frac{-7}{10}<\frac{2}{-\,\,3}<\frac{5}{-\,\,8}\]
Correct Answer: D
Solution :
| LCM of 10, 8, 3 = 240 |
| \[\frac{-7}{10}=\frac{168}{240}\]\[\Rightarrow \]\[\frac{-\,\,5}{8}=\frac{-150}{240}\] |
| \[\frac{-\,\,2}{3}=\frac{-160}{240}\] |
| Since, \[\frac{-168}{240}<\frac{-160}{240}<\frac{-150}{240}\] |
| \[\therefore \] \[\frac{-\,\,7}{10}<\frac{-\,\,2}{3}<\frac{-\,\,5}{8}\] |
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