| If \[a=0.1039,\]then the value of \[\sqrt{4{{a}^{2}}-4a+1}+3a\] is |
A) 0.1039
B) 0.2078
C) 1.1039
D) 2.1036
Correct Answer: C
Solution :
| \[a=0.1039\] |
| Now, \[\sqrt{4{{a}^{2}}-4a+1}+3a=\sqrt{{{(2a-1)}^{2}}}+3a\] |
| \[=\pm \,\,(2a-1)+3a\] |
| \[=-\,\,2a+1+3a\] [consider\[-\,\,(2a-1)\]] |
| \[=a+1=0.1039+1=1.039\] |
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