| A milk vendor has 21 L of cow milk, 42 L of toned milk and 63 L of double toned milk. If he wants to pack them in cans, so that each can contains same number of liters of milk and does not want to mix any two kinds of milk in a can, then the least number of cans required as [SSC (10+2) 2012] |
A) 3
B) 6
C) 9
D) 11
Correct Answer: D
Solution :
| Now. LCM of (21, 42, 63) =126 |
| Total number of cans \[=\frac{126}{21}+\frac{126}{42}+\frac{126}{63}\] |
| \[6+3+2=11\] |
| So, least number of cans is 11. |
You need to login to perform this action.
You will be redirected in
3 sec
