question_answer

Acid and water are mixed in a vessel A in the ratio of 5: 2 and in the vessel B in the ratio of 8: 5. In what proportion should quantities be taken out from the two vessels, so as to form a mixture in which the acid and water will be in the ratio of 9: 4?                                                                                                                                             [SSC (10+2) 2011]

A) 7 : 2

B) 2 : 7  

C) 7 : 4                             

D) 2 : 3

Correct Answer: A

Solution :

Quantity of acid in vessel A \[=\frac{5}{7}\]

Quantity of acid in vessel B \[=\frac{8}{13}\]

Quantity of acid in vessel C \[=\frac{9}{13}\]

By mixture method,

\[\therefore \]Required ratio \[=\frac{1}{13}:\frac{2}{91}=7:2\]