| Directions: In each of the following questions there are two equations. You have to solve both equations and give answer. [SBI (PO) 2015] |
| I. \[{{x}^{2}}+5x+6=0\] |
| II. \[2{{y}^{2}}+7y+6=0\] |
A) If \[x>y\]
B) If \[x\ge y\]
C) If \[x<y\]
D) If \[x\le y\]
E) If \[x=y\] of relation cannot be established
Correct Answer: D
Solution :
| I. \[{{x}^{2}}+5x+6=0\] |
| \[\Rightarrow \] \[{{x}^{2}}+2x+3x+6=0\] |
| \[\Rightarrow \] \[(x+2)(x+3)=0\] |
| \[\Rightarrow \] \[x=-\,2,\]\[x=-\,3\] |
| II. \[2{{y}^{2}}+7y+6=0\] |
| \[\Rightarrow \] \[2{{y}^{2}}+4y+3y+6=0\] |
| \[\Rightarrow \] \[2y\,(y+2)+3\,(y+2)=0\] |
| \[\Rightarrow \] \[(y+2)(2y+3)=0\] |
| \[\Rightarrow \] \[y=-\,2,\]\[\frac{-\,3}{2}\] |
| \[\therefore \] \[x\le y\] |
You need to login to perform this action.
You will be redirected in
3 sec
