If \[{{(0.64)}^{4}}\div {{(0.512)}^{3}}\times {{(0.8)}^{4}}={{(0.8)}^{x+3}},\] then the value of x is [IOB (PO) 2011] |
A) 5
B) 12
C) 0
D) 6
E) None of these
Correct Answer: C
Solution :
\[\frac{{{(0.64)}^{4}}}{{{(0.512)}^{3}}}\times {{(0.8)}^{4}}={{(0.8)}^{x+3}}\] |
\[\Rightarrow \] \[\frac{{{(0.8)}^{8}}}{{{(0.8)}^{9}}}\times {{(0.8)}^{4}}={{(0.8)}^{x+3}}\] |
\[\Rightarrow \] \[{{(0.8)}^{3}}={{(0.8)}^{x+3}}\]\[\Rightarrow \]\[x+3=3\] |
\[\therefore \] \[x=0\] |
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