| A student goes to school at the rate of \[2\frac{1}{2}\,km/h\] and reaches 6 min late. If he travels at the speed of 3 km/h, he is 10 min early The distance (in km) between the school and his house is [SSC (CGL) 2011] |
A) 5
B) 4
C) 3
D) 1
Correct Answer: B
Solution :
| Let \[x=\frac{5}{2},\]\[y=3,\]\[{{t}_{1}}=6,\]\[{{t}_{2}}=10\] |
| \[\therefore \] Required distance \[=xy\,\frac{({{t}_{1}}+{{t}_{2}})}{y-x}\] |
| \[=\frac{3\times \frac{5}{2}\times (6+10)}{3-5/2}\] |
| \[=\frac{15}{2}\times \frac{16}{60}\times \frac{2}{1}=4\,km\] |
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