Area of the triangle formed by the graph of the straight lines \[x-y=0,\]\[x+y=2\] and the X-axis is |
[SSC (CGL) Mains 2014] |
A) 1 sq unit
B) 2 sq units
C) 4 sq units
D) None of the above
Correct Answer: A
Solution :
From figure, |
\[\Delta AOB\] is made by given lines, where A (1, 1), O(0, 0) and B (2, 0) are coordinates. |
Here, \[{{x}_{1}}=1,\]\[{{y}_{1}}=1,\]\[{{x}_{2}}=0\] |
\[{{y}_{2}}=0,\]\[{{x}_{3}}=2,\]\[{{y}_{3}}=0\] |
\[\therefore \] Area of \[\Delta AOB=\frac{1}{2}\,\,[{{x}_{1}}({{y}_{2}}-{{y}_{3}})\] |
\[+{{x}_{2}}({{y}_{3}}-{{y}_{1}})+{{x}_{3}}({{y}_{1}}-{{y}_{2}})]\] |
\[=\frac{1}{2}[1\,(0-0)+0\,(0-1)+2\,(1-0)]\] |
\[=\frac{1}{2}[1\times 0+0\times (-1)+2\times 1]\] |
\[=\frac{1}{2}\,\,[0-0+2]=\frac{1}{2}\times 2=1\,\text{sq}\,\text{unit}\] |
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