| The area of a square is \[1024\,c{{m}^{2}}.\] What is the respective ratio between the length and the breadth of a rectangle whose length is twice the side of the square and breadth is 12 cm less than the side of the square? |
A) 5 : 18
B) 16 : 7
C) 14 : 5
D) 32 : 5
E) None of these
Correct Answer: E
Solution :
| Area of a square \[={{a}^{2}}=1024\] |
| \[\therefore \] \[a=\sqrt{1024}=32\,cm\] |
| Breadth of the rectangle = 12 cm less than the side of the square \[=32-12=20\,cm\] |
| Length of the rectangle = Twice the side of the square |
| \[=2\times 32=64\,cm\] |
| Ratio of length and breadth\[=\,64\,:\,20\,=\,64cm\] |
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