question_answer

Directions: In each of the given questions, one question and two statements numbered I and II are given. You have to decide whether the data given in both the statements are, sufficient to answer the question or not. Read both the statements and give answer.                                                                                      [IBPS (SO) IT 2015]

Neeraj invested certain amount in schemes A and B for 2 yr in the ratio of 3: 5 respectively. The schemes A and B offer compound interest compounded, annually and simple interest respectively. What is the amount invested in scheme A?

I. Rate of interest offered by scheme A is 20% per annum and the rate of interest offered by scheme B is 25% less than that offered by scheme A.

II. Amount of interest accrued from scheme B is more than the amount of interest accrued from scheme A by Rs. 900.

A) If the data in statement I alone are sufficient to answer the question, while the data in statement II alone are not sufficient to answer the question

B) If the data in statement II alone are sufficient to answer the question, while the data in statement I alone are not sufficient to answer the question

C) If the data either in statement I alone or in statement II alone are sufficient to answer the question

D) If the data in both the statements I and II together are not sufficient to answer the question

E) If the data in both the statements I and II together are necessary to answer the question

Correct Answer: E

Solution :

\[\Rightarrow \]\[\frac{5x\times 15\times 2}{100}-\left\{ 3x{{\left( 1+\frac{20}{100} \right)}^{2}}-3x \right\}=900\]

\[\Rightarrow \]   \[\frac{3x}{2}-\left\{ 3x\times \frac{36}{25}-3x \right\}=900\]

\[\Rightarrow \]   \[\frac{3x}{2}-\left\{ \frac{108x-75x}{25} \right\}=900\]

\[\Rightarrow \]   \[\frac{75x-66x}{50}=900\]

\[\Rightarrow \]   \[9x=900\times 50=Rs.5000\]

Amount invested in scheme

\[A=3\times 5000=15000\]