| In a number of two digits, units place digit is 2 more than the tens place digit. Four times the sum of digits is 3 less than the number, then the number is |
A) 35
B) 57
C) 46
D) 68
Correct Answer: A
Solution :
| Let unit's place digit be x and ten's place digit be y. |
| \[\therefore \] Number \[=10y+x\] |
| According to the question, |
| \[x-y=2\] (i) |
| and \[4(x+y)=10y+x-3\] |
| \[\Rightarrow \] \[3x-6y=-3\] |
| \[\Rightarrow \] \[x-2y=-1\] (ii) |
| On solving Eqs. (i) and (ii), we get |
| x = 5 and y = 3 |
| Hence, number \[=10y+x\] |
| \[=10\times 3+5=35\] |
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