| A trader sold a pen at a loss of 20%. If he sells the pen at Rs. 12 more he would have gained 10%. The cost price of the pen (in Rs.) is |
A) 60
B) 40
C) 30
D) 22
Correct Answer: B
Solution :
| Let the CP of the pen be x. |
| Then, selling price \[=100\times \frac{(x-20)}{100}=\frac{4x}{5}\] |
| According to the question, |
| \[\frac{4x}{5}+12=x+\frac{10}{100}\times x\] |
| \[\Rightarrow \] \[\frac{4x}{5}\times 12=\frac{11x}{10}\]\[\Rightarrow \]\[12=\frac{11x}{10}-\frac{4x}{5}\] |
| \[\Rightarrow \] \[12=\frac{11x-8x}{10}\]\[\Rightarrow \]\[\frac{120}{3}=x\] |
| \[\Rightarrow \] \[x=Rs.\,40\] |
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