| Directions: In the following question, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer. [IBPS (Officer Recruitment) 2015] |
| Give answer |
| I. \[{{x}^{2}}-3x-88=0\] |
| II. \[{{y}^{2}}+8y-48=0\] |
A) if \[x\ge y\]
B) if \[x\le y\]
C) if \[x<y\]
D) if \[x>y\]
E) if relationship between x and y cannot be established
Correct Answer: D
Solution :
| I. \[{{x}^{2}}-3x-88=0\] |
| \[\Rightarrow \] \[{{x}^{2}}-11x+8x-88=0\] |
| \[\Rightarrow \] \[x\,(x-11)+8\,(x-11)=0\] |
| \[\Rightarrow \] \[(x+8)(x-11)=0\] |
| \[\Rightarrow \] \[x=-\,8\,or\,11\] |
| II. \[{{y}^{2}}+8y-48=0\] |
| \[\Rightarrow \] \[{{y}^{2}}+12y-4y-48=0\] |
| \[\Rightarrow \] \[y\,(y+12)-4\,(y+12)=0\] |
| \[\Rightarrow \] \[(y-4)(y+12)=0\]\[\Rightarrow \]\[y=-12\,\,or\,\,4\] |
| Hence, x > y |
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