| Two cars start from place A and B, 100 km apart, towards each other. Both cars start simultaneously. A bird sitting on one car starts at the same time towards the other car and as soon as it reaches the second car, it flies back to the first car and it continues in this manner flying backwards and forwards from one car to the other, until the cars meet. Both cars travel at a speed on 50 km/h and the bird flies at 100 km/h. Total distance covered by the bird will be |
| [FCI (Assistant) Grade III 2015] |
A) 50 km
B) 100 km
C) 200 km
D) None of these
Correct Answer: B
Solution :
| Total distance travelled by the bird = Speed \[\times \] Time |
| \[=100\times 1=100\,km\] |
| \[\left[ \because \text{time}\,\,\text{=}\,\,\frac{\text{distance}\,\text{between}\,\text{A}\,\text{and}\,\text{B}}{\text{relative}\,\text{speed}\,\text{of}\,\text{cars}}=\frac{100}{50+50}=1\,h \right]\] |
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