| Pipe A can fill an empty tank in 6 h and pipe B in 8 h. If both the pipes are opened and after 2 h pipe A is closed, then how much time pipe B will take to fill the remaining tank? [SSC (CGL) Pre 2015] |
A) \[7\frac{1}{2}h\]
B) \[3\frac{1}{3}h\]
C) \[2\frac{2}{5}h\]
D) \[2\frac{1}{3}h\]
Correct Answer: B
Solution :
| A's one hour's work \[=\frac{1}{6}\] |
| B's one hour's work \[=\frac{1}{8}\] |
| \[(A+B)'s\] two hour's work \[=2\left( \frac{1}{8}+\frac{1}{6} \right)=\frac{28}{48}\] |
| \[\therefore \] Remaining work \[=1-\frac{28}{48}=\frac{20}{48}\] |
| Time taken by pipe B to complete remaining work |
| \[=\,\,\frac{\frac{20}{48}}{\frac{1}{8}}\,\,=\,\,\frac{20}{48}\times 8=\frac{20}{6}=3\frac{1}{3}h\] |
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