A) 7 min 30 sec
B) 8 min 5 sec
C) 8 min 20 sec
D) 8 min 15 sec.
Correct Answer: D
Solution :
[d] Work done by both pipes in 1 min \[=\frac{1}{12}+\frac{1}{15}=\frac{9}{60}\] Work done in 3 min\[=\frac{9}{60}\times 3=\frac{9}{20}\] Remaining work \[=1-\frac{9}{20}=\frac{11}{20}\] B fill 1 tank in 15 min B fill\[\frac{11}{20}\]part in \[=15\times \frac{11}{20}=\frac{33}{4}=8\,\,\min \,\,15\,\,\sec .\]
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