A) 10 hrs.
B) 15 hrs.
C) 20 hrs.
D) 30 hrs.
Correct Answer: D
Solution :
[d] A + B fill in 6 hrs. B + C fill in 10 hrs. A + C fill in \[7\frac{1}{2}=\frac{15}{2}hrs\] \[\therefore \,\,2(A+B+C)\] fill in \[\frac{6\times 10\times \frac{15}{2}}{6\times 10+6\times \frac{15}{2}+10\times \frac{15}{2}}=\frac{6\times 5\times 15}{180}=\frac{5}{2}\] \[\therefore \] A + B + C filled the tank in 5 hrs. Now, \[A[=(A+B+C)-(B+C)]\,\,fill\,\,in\,\,\frac{10\times 5}{10-5}=10\,hrs.\] Similarly, B fill in \[\frac{\frac{15}{2}\times 5}{\frac{15}{2}-5}=15hrs\]and C fill in \[\frac{5\times 6}{6-5}=30hrs.\]You need to login to perform this action.
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