question_answer

A certain simple harmonic vibrator of mass 0.1 kg has a total energy of 10 J. Its displacement from the mean position is 1 cm when it has equal kinetic and potential energies. The amplitude A and frequency n of vibration of the vibrator are

A) \[A=\sqrt{2}\,cm,n=\frac{500}{\pi }Hz\]

B) \[A=\sqrt{2}cm,n=\frac{1000}{\pi }Hz\]

C) \[A=\frac{1}{\sqrt{2}}cm,n=\frac{500}{\pi }Hz\] 

D) \[A=\frac{1}{\sqrt{2}}cm,n=\frac{1000}{\pi }Hz\]