Answer:
\[{{V}_{A}}-{{V}_{B}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{Q}{OA}-\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{Q}{OB}=\frac{Q}{4\pi {{\varepsilon }_{0}}}\left[ \frac{1}{OA}-\frac{1}{OB} \right]\] From the diagram the distance OA < OB. \[\therefore \frac{1}{OA}-\frac{1}{OB}\] is positive.
(i) If Q is positive, then \[{{V}_{A}}-{{V}_{B}}\] is positive. (ii) If 0 is negative, then \[{{V}_{A}}-{{V}_{B}}\] is negative.
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