Answer:
The equivalent resistance of the circuit \[{{R}_{aq}}=\frac{{{R}_{0}}}{2}+\frac{R\cdot ({{R}_{0}}/2)}{R+({{R}_{0}}/2)}\] \[\therefore \] Current in the circuit, \[I=\frac{N}{{{R}_{aq}}}\] \[V=I{{R}_{aq}}=I\left[ \frac{{{R}_{0}}}{2}+\frac{R\cdot ({{R}_{0}}/2)}{R+({{R}_{0}}/2)} \right]\] \[=I\left( \frac{{{R}_{0}}}{2}+\frac{R{{R}_{0}}}{2R+{{R}_{0}}} \right)\] \[\therefore \] \[V=\frac{I{{R}_{0}}}{2}\left( 1+\frac{2R}{2R+{{R}_{0}}} \right)\]
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