Answer:
Lorentz magnetic force, \[{{F}_{m}}=q(v\times B)\] Work done by Lorentz magnetic force is \[dW={{F}_{m}}\cdot s={{F}_{m}}\cdot v\,dt\] \[W=\int{{{F}_{m}}\cdot v\,\,dt=\int{q(v\times B)}\cdot v\,\,dt}\] W = 0 \[[\because (v\times B)\bot v,\] and \[(v\times B)\cdot v=0]\] Therefore, no work is done by this force on the charged particle.
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