A) 18 kg
B) 17 kg
C) 16.5 kg
D) 16 kg
Correct Answer: D
Solution :
[d] 96% of 20 kg \[=\frac{96}{100}\times 20=19.2\,\,kg\] [wt. of water] Let ?x? kg of water in evaporated, then \[19.2-x=95%\,\,of\,\,(20-x)\] \[\Rightarrow \] \[19.2-x=\frac{95\times (20-x)}{100}\] \[\Rightarrow \] \[1920-100x=1900-95x\] \[\Rightarrow \] \[5x=20\] \[\Rightarrow \] \[x=4\,kg\] \[\therefore \] Reduced wt =20 ? 4 = 16 kgYou need to login to perform this action.
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