A) Cube of 2
B) Lies between 6 and 10
C) 6
D) Lies between 3 and 6
Correct Answer: D
Solution :
[d] Unit digit in \[{{7}^{95}}\] = [Unit digit in\[{{({{7}^{4}})}^{23}}\times {{7}^{3}}\]] \[=\left[ 1\times 343 \right]\text{ }=\text{ }343\] Unit digit in \[{{3}^{58}}\] = [Unit digit in\[{{({{3}^{4}})}^{14}}\times {{3}^{2}}\]] \[=\left[ 1\times 9 \right]=9\] So unit digit in \[{{7}^{95}}-{{3}^{58}}\] = Unit digit in [343 ? 9] = Unit digit in 334 = 4 So the answer is 4.
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