question_answer

Let D be the mid-point of a straight line AB and let C be a point different from D such that CA = CB. Then which one of the following is correct?

A) \[\angle CDB\]is acute

B) \[\angle CDB>\]90°

C) \[\angle CDB={{90}^{\text{o}}}\]

D) \[CA\bot AB\]

Correct Answer: C

Solution :

CD is perpendicular to AB \[\Rightarrow \,\,\,\angle CDB=90{}^\circ \]