A) \[(2x-3y+z)\]
B) \[(2x-3y-z)\]
C) \[(2x+3y-z)\]
D) \[(2x-3y+z)\]
Correct Answer: B
Solution :
[b] One of the factors of \[{{a}^{3}}+{{b}^{3}}+\text{ }{{c}^{3}}-\]3abc is (a + b + c) Now \[8{{x}^{3}}-27\text{ }{{y}^{3}}-{{z}^{3}}-18\text{ }xyz\]can be written as \[{{\left( 2x \right)}^{3}}+{{\left( -3y \right)}^{3}}+{{\left( -z \right)}^{3}}-3\left( 2x \right)\left( -3y \right)\left( -z \right)\] One of the factors is \[2x-3y-z.\]
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